The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem?

3n2 + 5 = 116

3n2 + 3n + 3 = 116

3n2 + 6n + 5 = 116

Question

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?

Which of the following equations is used in the process of solving this problem? 



3n2 + 5 = 116


3n2 + 3n + 3 = 116


3n2 + 6n + 5 = 116

anonymous · Answer

How do you think  would you solve this?

anonymous · Answer

idk

anonymous · Answer

Well, think about it. Let's say the first number is $n$, then the next is $n + 1$, and the last one will be $n+2$

anonymous · Answer

sooooo n+n+1+n+2=116 or no???

triciaal · Answer

The sum of the squares

triciaal · Answer

n^2 + (n + 1)^2 + (n+ 2)^2 = 116

anonymous · Answer

ok sooo divide the equation by two right

triciaal · Answer

no

triciaal · Answer

n^2 + (n + 1)^2 + (n+ 2)^2 = 116

triciaal · Answer

expand the parenthesis 
group like terms 
you are just adding    the sum

triciaal · Answer

3 n^2 +  (2 + 4) n + (1 + 4)  = 116 
3 n^2 + 6 n + 5 = 116   Choice D

anonymous · Answer

ohh ok thanks

triciaal · Answer

you are welcome 

What are the numbers?  do you need ?