How do I find x?
f(x) = sin(x) - tan(x) when x = pi/4, find f(x). f(pi/4) = ? (x, ?) is a point on the curve and also on the tangent. ---- (1) What is the slope of the curve at x = pi/4 ? The derivative gives the slope. Find f'(x) and then f'(pi/4) f'(pi/4) = ? ---- (2) Equation of tangent is: y = mx + b m is the slope. Sub from (2) (1) gives a point on the line. Sub x and y values and solve for b.
\[ f(x) = \sin(x) - \tan(x) \\ f(\pi/2) = \sin(\pi/2) - \tan(\pi/2) = \frac{\sqrt{2}}{2} - 1 = \frac{\sqrt{2}-2}{2} \\ f'(x) = \frac{d}{dx}\sin(x) - \frac{d}{dx}\tan(x) = \cos(x) - \sec^2(x) \\ f'(\pi/2) = \cos(\pi/2) - \sec^2(\pi/2) = \frac{\sqrt{2}}{2} - \left(\frac{2}{\sqrt{2}}\right)^2 = \frac{\sqrt{2}}{2} - \frac{4}{2} = \frac{\sqrt{2}-4}{2}\\ \]You can find the equation of the tangent knowing the slope and a point on the line.
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