How do we solve -3(x)+6<-9 and graph it?
First you need to simplify it
So I got x<5
But like how does this happen : x<5 or -5<x ?
so you reduce it to -3x < -15, then divide by -3. When you divide or multiply by a negative number, the inequality sign flips. For example -1*3 = -3 < 5, but if you divide both sides by -1 you get 3 on the left and -5 on the right, and so the inequality flips. Now to graph it, you include in the graph all possible values of x. Which in this case, means all numbers that fit > 5.
-3x<-15 it would actually be x>5 because a negative divided by a negative becomes a positive and when you divide by a negative you are supposed to flip the inverse sign
And what bout this one 5(x-3)-8>2
how far are you into it?
Well I got x>5
so 5(x-3) > 10, x - 3 > 2, x > 5. that seems solid
But my teacher said the right answer is 1<x<5 and I don't know why
so if you plug in a 2 there (which is in the range your teacher describes), you get 5(2-3) - 8 = 5(-1) -8 = -5 -8 = -13 which is not greater than 2.
Are you sure you're being asked to solve for x?
or that all the signs are right?
It just says that we should graph and answer to make the equation true
What does graphing involve for you guys?
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