If f(x) = cscx, find f""(pi/3)
Hey Camila c: Where you gettin stuck? Able to find your first derivative?
How many ticks is that on the f? Is that 4? It's hard to read them when they're all jammed together like that >.<
Sorry it was only to be 2 ticks. Im not sure where to start with this problem. Do I change it to -cscxcotx and then do the product rule?
Mmm yah your first derivative looks good :) Yessss, product rule for the second derivative.\[\Large\rm f''(x)=\color{royalblue}{\left(-\csc x\right)'}\cot x-\csc x\color{royalblue}{\left(\cot x\right)'}\]
And from there I plug in my value for pi/3 into that equation right?
Well you have to take the derivative of the blue parts first. I only setup the product rule. But yes, after you've got that taken care of, plug in the pi/3's
Okay thank you so much!
k c:
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