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Mathematics 9 Online
OpenStudy (anonymous):

If f(x) = cscx, find f""(pi/3)

zepdrix (zepdrix):

Hey Camila c: Where you gettin stuck? Able to find your first derivative?

zepdrix (zepdrix):

How many ticks is that on the f? Is that 4? It's hard to read them when they're all jammed together like that >.<

OpenStudy (anonymous):

Sorry it was only to be 2 ticks. Im not sure where to start with this problem. Do I change it to -cscxcotx and then do the product rule?

zepdrix (zepdrix):

Mmm yah your first derivative looks good :) Yessss, product rule for the second derivative.\[\Large\rm f''(x)=\color{royalblue}{\left(-\csc x\right)'}\cot x-\csc x\color{royalblue}{\left(\cot x\right)'}\]

OpenStudy (anonymous):

And from there I plug in my value for pi/3 into that equation right?

zepdrix (zepdrix):

Well you have to take the derivative of the blue parts first. I only setup the product rule. But yes, after you've got that taken care of, plug in the pi/3's

OpenStudy (anonymous):

Okay thank you so much!

zepdrix (zepdrix):

k c:

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