how would you begin to sketch the graph of the equation. x = 3y2 − 9

Question

campbell_st · Answer

well I would look at the fact the x-axis is the line of symmetry

factor it

x=(y -3)(y + 3)

so now I know the y- intercepts... 

and when y = 0 the x intercept is x = -9

I also know the curve is concave right

hope it helps

triciaal · Answer

one approach 
put in the form y = 
find the value of y when x = 0  point (0. y)
find the value of x when y = 0  point (x, 0)
need the minimum of 2 points to sketch a line you will now have these 2 points

campbell_st · Answer

ooops... for got yo say its a parabola

triciaal · Answer

@campbell_st since the x and y 's are switched would this be a horizontal parabola?

campbell_st · Answer

opps made a mistake with the y intercepts... misread the question the factored from is 

$$x = 3(y - \sqrt{3})(y + \sqrt{3})$$

campbell_st · Answer

it is a parabola that opens to the right... and easy way to look at it is with https://www.desmos.com/calculator

triciaal · Answer

@campbell_st thank you