Ask your own question, for FREE!
Chemistry 10 Online
OpenStudy (anonymous):

If 6.40 k cal of heat is added to 1.00 kg of ice at 0⁰C, how much liquid water at 0⁰C is produced?

OpenStudy (anonymous):

i honestly am lost on this question

OpenStudy (anonymous):

heat,Q=mlf, lf=latent heat of fusion use this equation to solve your prblem p.s- be careful about the units. at first convert them to S.I unit

OpenStudy (anonymous):

wait what? can you dumb it down a tad more for me please i don't remember learning any of this

OpenStudy (anonymous):

okay, here Q=6.4k cal=6.4 x 1000 x 4.2J Lf= 3.36 x 10^5 so, m= Q/Lf hope that helps

OpenStudy (anonymous):

so you multiply Q & LF? or divide them?

OpenStudy (anonymous):

Q=m x Lf so to find out m we have to divide Q by Lf

OpenStudy (anonymous):

Q-26880 then you divide 33600?

OpenStudy (anonymous):

gives you 12.5

OpenStudy (anonymous):

Lf= 336000

OpenStudy (anonymous):

|dw:1412946755810:dw|

OpenStudy (anonymous):

is that all?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!