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If 6.40 k cal of heat is added to 1.00 kg of ice at 0⁰C, how much liquid water at 0⁰C is produced?
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i honestly am lost on this question
heat,Q=mlf, lf=latent heat of fusion use this equation to solve your prblem p.s- be careful about the units. at first convert them to S.I unit
wait what? can you dumb it down a tad more for me please i don't remember learning any of this
okay, here Q=6.4k cal=6.4 x 1000 x 4.2J Lf= 3.36 x 10^5 so, m= Q/Lf hope that helps
so you multiply Q & LF? or divide them?
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Q=m x Lf so to find out m we have to divide Q by Lf
Q-26880 then you divide 33600?
gives you 12.5
Lf= 336000
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is that all?
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