Question

Flying against the wind, a jet travels
3080mi in 4 hours. Flying with the wind, the same jet travels 8610mi in 7 hours. What is the rate of the jet in still air and what is the rate of the wind?

Answer 1

if rate is referring to speed then the initial speed without wind is 770mph compared to 1230mph with wind

Answer 2

rate is simply reference to something in relation to time, so this is mph of the jet,

Answer 3

They ask for the Rate of the wind and the Rate of Jet still in Air
So there are two answers

Answer 4

?

Answer 5

let 'x' be the velocity of the jet
'y' be the velocity of the wind
flying against the wind the traveled distance is 3080mi in 4hrs
note that distance=velocity x time
since time is 4 hours and we know that the wind is in opposite direction with the jet then you'll have the equation,
x(4) - y(4) = 3080 ---equation 1
flying with the wind you'll have the distance as 8610 mi and time = 7hours
applying the same idea you'll have
x(7) + y(7) = 8610 ---equation 2
multiplying equation 1 with 7 and equation 2 with 4 you'll have:
(4x - 4y = 3080)(7)
28x - 28y = 21,560 ---equation 1'
(7x + 7y = 8610)(4)
28x + 28y = 34,440 ---equation 2'
subtract equation 1' from 2'
28x + 28y = 34,440
(-) 28x - 28y = 21,560
56y = 12,880
y = 230mph
substitute to equation 1
4x - 4y = 3080
4x - 4(230) = 3080
4x = 3080 + 920
4x = 4000
x = 1000mph