Question

hello
could you help me on this exponents question

Answer 1

it is given that
\[2^{2x-1}= 3^{1-x} \]
find the value of
\[12^{x}\]

Answer 2

hende find the value of x

Answer 3

hence*

Answer 4

\[2^{2x-1}=2^{2x}*2^{-1}\]

Answer 5

\[=\frac{ 2^{2x} }{ 2 }\]

Answer 6

yes but i still can't get it

Answer 7

\[\frac{ (2^{2})^{x} }{ 2 }\]

Answer 8

u got what i m doing ???

Answer 9

yes

Answer 10

12^x= (3*4)^x
(3*2^2)^x

Answer 11

\[=3^{x}*2^{2x}\]

Answer 12

it is 12^x we broke it into 2 and 3

Answer 13

yes

Answer 14

upto here u got me right ??

Answer 15

yes

Answer 16

on left side we got
\[\frac{ (2^{2})^{x} }{ 2 }\]

Answer 17

now on right side

Answer 18

\[3^{1-x}=3*3^{-x}\]

Answer 19

\[\frac{ (2^2)^{x} }{ 2 }=3*3^{-x}\]

Answer 20

yes i understand until there
now multiply both sides by 3^x ?

Answer 21

yeah

Answer 22

and thn also multiply by 2 on both side

Answer 23

i got it
12^x = 6

Answer 24

to eliminate 2

Answer 25

you are the best
thank you so much

Answer 26

yeah u got it ...very good :)

Answer 27

loll i m not the best..n welcme btw :)