Question

An aqueous solution freezes at -3.47⁰C. What is its boiling point?

Answer 1

@JFraser @Abmon98 @kavonta @bibby @micahm @Tj1014

Answer 2

101.13°C

Answer 3

how so? i was told this:
The molar freezing point depression constant for water is 1.86°C/mol. You have a solution that freezes at -3.47°C. Therefore it is 3.47 /1.86 = 1.9 molar solution
The boiling point elevation for water is 0.512°C/mol
You have a 1.9m solution, so the solution will have boiling point elevation = 0.512*1.9 = °C

Answer 4

The molal freezing point depression constant for water is 1.86°C/mol. You have a solution that freezes at -4.09°C. Therefore it is 4.09/1.86 = 2.2 molal solution

The boiling point elevation for water is 0.512°C/mol
You have a 2.2m solution, so the solution will have boiling point elevation = 0.512*2.2 = 1.13°C

Answer 5

he right

Answer 6

i dont have that question tho. its not -4.09 degrees its -3.47 degrees

Answer 7

so what are you looking for

Answer 8

the boiling point of -3.47 Degrees

Answer 9

On the Fahrenheit scale, the freezing point of water is 32 degrees Fahrenheit (°F) and the boiling point is 212 °F (at standard atmospheric pressure). This puts the boiling and freezing points of water exactly 180 degrees apart.

Answer 10

alright.

Answer 11

do you need more info

Answer 12

i need more help to solve the problem :
3.47/1.86=1.86

Answer 13

then 0.512*1.86 = 0.95232°C ?

Answer 14

@JFraser can you please help me?

Answer 15

is this a math problem if so i have a site that can help you

Answer 16

www.freemathhelp.com

Answer 17

its a chemistry question.

Answer 18

use the freezing point depression to find the molality of the solution, as @Tj1014 says. then plug that same molality into the boiling point expression.

the only difference between the two formulas is the value of K. The Kf of water is -1.86C/molal, but the Kb of water is 0.512C/molal

\[\Delta T_f = K_f*m\]and\[\Delta T_b = K_b*m\]

Answer 19

delta TF = -1.86*m
delta TB= 0.512*m
What is M?

Answer 20

No. \(\Delta T_f\) is -3.47C. The problem tells you that. Use the first set of information to find m, then plug that m into the second equation and solve for \(\Delta T_b\)

Answer 21

so -3.47*-1.86 to find delta TF

Answer 22

no. it tells you \(\Delta T_f\) = -3.47C. Solve the first equation for \(m\)