If A=x^2 and dx/dt=3, find dA/dt|x= 10 how do i do this because it also says to find dx/dt|x=10 and dA/dt=3
lol no
\[A=x^2, A'=2xx'\]
you are told \(x'=3\) and \(x=10\) so \[A'=2\times 10\times 3=60\]
since the dx/dt notation sucks,i replaced it by \(x'\) which is easier to write
hope the answer was clear
If A=x^2 and dx/dt=3, find dA/dt|x= 10 dA/dx = 2 x dA/dx*dx/dt = dA/dt substitute 2 x * 3 = 10 x = 10/6 = 5/3
what is the original question?
A=x^2 is the equation then it says to do the two things
are you to find dA/dt when x = 10 given that dx/dt = 3 and dA/dt when x = 3
are those the 2 things?
yes two separate
yes that makes sense now
dA/dx*dx/dt = dA/dt x = 10 and dx/dt = 3 dA/dx = 2 x = 2 * 10 = 20 substituting dA/dt = 20*3 = 60
but i dont get what the diference si between dx/dt and dA/dt
dA/dt when x = 3
dx/dt function x changing with t da/dt change in area with respect to t
dx/dt = 3 and x = 3 da/dt = da/dx*dx/dt = 2 * 3 * 3 = 18
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