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OpenStudy (anonymous):
If A=x^2 and dx/dt=3, find dA/dt|x= 10
how do i do this
because it also says to find dx/dt|x=10 and dA/dt=3
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OpenStudy (anonymous):
lol no
OpenStudy (anonymous):
\[A=x^2, A'=2xx'\]
OpenStudy (anonymous):
you are told \(x'=3\) and \(x=10\) so
\[A'=2\times 10\times 3=60\]
OpenStudy (anonymous):
since the dx/dt notation sucks,i replaced it by \(x'\) which is easier to write
OpenStudy (anonymous):
hope the answer was clear
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OpenStudy (triciaal):
If A=x^2 and dx/dt=3, find dA/dt|x= 10
dA/dx = 2 x
dA/dx*dx/dt = dA/dt
substitute
2 x * 3 = 10
x = 10/6 = 5/3
OpenStudy (triciaal):
what is the original question?
OpenStudy (anonymous):
A=x^2 is the equation then it says to do the two things
OpenStudy (triciaal):
are you to find dA/dt when x = 10 given that dx/dt = 3 and dA/dt when x = 3
OpenStudy (triciaal):
are those the 2 things?
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OpenStudy (anonymous):
yes two separate
OpenStudy (triciaal):
yes that makes sense now
OpenStudy (triciaal):
dA/dx*dx/dt = dA/dt
x = 10 and dx/dt = 3
dA/dx = 2 x = 2 * 10 = 20
substituting
dA/dt = 20*3 = 60
OpenStudy (anonymous):
but i dont get what the diference si between dx/dt and dA/dt
OpenStudy (triciaal):
dA/dt when x = 3
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OpenStudy (triciaal):
dx/dt function x changing with t
da/dt change in area with respect to t
OpenStudy (triciaal):
dx/dt = 3 and x = 3
da/dt = da/dx*dx/dt = 2 * 3 * 3 = 18
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