Question

Please help

http://prntscr.com/4uv9jd

Answer 1

Hey Virg :)
Looks like we can probably use the Law of Cosines for this problem.

Answer 2

\[\Large\rm c^2=a^2+b^2-2ab \cos \mathcal C\]That formula, yah? :d

Answer 3

\[\Large\rm c^2=4.7^2+6.1^2-2(4.7)(6.1)\cos47^o\]

Answer 4

\[\Large\rm c=\sqrt{4.7^2+6.1^2-2(4.7)(6.1)\cos47^o}\]

Answer 5

And then just rely on your good ole calculator from there :)

Answer 6

i got 4.493796835639

Answer 7

Yay \c:/ Good job!

Answer 8

so wait thats still not my answer

Answer 9

Ohhh the question was areaaaa :(
Ahhh sorry.

Answer 10

\[\Large\rm A=\frac{1}{2}a b \sin(\theta)\]Where theta is the angle BETWEEN sides a and b.
\[\Large\rm A=\frac{1}{2}(4.7)(6.1)\sin(47^o)\]

Answer 11

We didn't need to do the Law of Cosines, my bad :c

Answer 12

10.483955312708 a

Answer 13

yay good job \c:/