Solve 5x^2 = -30x - 65.
I think it's x= -3 + 4i but i'm not sure.
well rewrite it and divide every term by 5 \[x^2 + 6x = 13\] complete the square \[x^2 + 6x + 9 = 13 + 9\] which becomes \[(x + 3)^2 = 22\] now you can solve for x
I'm not sure what to substitute in for x... @campbell_st
Wait, is it x = -6 + 2i
@campbell_st
How were you taught to solve this type problem?
I wasn't that's the thing.
There are 3 ways (1) factoring (won't work for this problem) (2) quadratic formula (3) complete the square any sound familiar?
I know factoring..that's it
I would start with 5x^2 = -30x - 65 and put it into standard form. Can you do that ?
ok so if \[(x + 3)^2 = 22\] taking the square root of both sides gives \[x + 3 = \pm \sqrt{22}\] perhaps this helps... to solve for x
standard form means ax^2 + bx + c = 0
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