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〖lim〗(x→1 )〖(x2-1)/(x-1)〗
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It is looking a bit weird to me.
I will try to guess what I'm seeing... \[\lim_{x \rightarrow 1}\frac{x^2-1}{x-1}\]?
If that is the problem, here is a hint to the problem: Factor the top and then cancel a common factor.
ok ((
what do you get when you factor x^2-1?
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i don't no
a^2-b^2=(a-b)(a+b)
\[\left( \times +1 \right)\]
x+1 is what you get when the (x-1)'s cancel
So since x+1 is continuous at x=1 you can easily find the limit now but just plugging in 1
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(x+1)(x-1)/(x-1)= (x+1)
right
But you to take care of the limit part now
yaay thank u (:
np
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