Question

cos150degrees - 3 tan300 degrees + 2 sin 90degrees

any mathematician can help me here

Answer 1

@gorv

Answer 2

150 degree comes in second quadrent

Answer 3

i found the value already but how can i sovle this....wait i will type

Answer 4

so cos give negative value in second quad

Answer 5

\[\frac{ -\sqrt{3} }{ 2 }- 3(-\sqrt{3}) + 2\]

Answer 6

i found this value but how can i simplify this bro..do you know please help me buddy :D

Answer 7

yeah ur right

Answer 8

okk i will

Answer 9

take 3 inside the bracket

Answer 10

both term have minus sign and are in multiplication

Answer 11

whenever there are 2 term and both are in multiplication then minus sign become plus

Answer 12

can u draw or write it so i can understand it quikly buddy :D

Answer 13

okk lets replace sqrt by x

Answer 14

\[\frac{ -x }{ 2 }-3*(-x)+2\]

Answer 15

\[\frac{ -x }{ 2 }+3x+2\]

Answer 16

can u do it now ??

Answer 17

so that means \[\frac{ -\sqrt{3} }{ 2 }+3\sqrt{3} + 2\]

Answer 18

is that the lowest tem for it?

Answer 19

@gorv

Answer 20

\[\sqrt{3}*(\frac{ -1 }{ 2 }+3)+2\]

Answer 21

\[\frac{ 5 }{ 2 }*\sqrt{3}+2=\frac{ 5\sqrt{3} +4}{ 2 }\]