Find two numbers whose product is a maximum when the sum of half the first number and ten times the second number is 100
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OpenStudy (anonymous):
@gymnast4Jesus<3
OpenStudy (anonymous):
Oh, you are not so good in tagging someone.. :P
OpenStudy (anonymous):
haha i know im sorry
OpenStudy (anonymous):
do you have any idea how to solve this problem?
OpenStudy (anonymous):
@gorv wanna continue with Regina??
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OpenStudy (anonymous):
please i beg. need all the help i can get
OpenStudy (gorv):
only if u r not willing to do it :P
OpenStudy (anonymous):
Okay, I am not willing.. :P
OpenStudy (anonymous):
:/
OpenStudy (anonymous):
What is that simile for??
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OpenStudy (gorv):
let first number is =x
OpenStudy (anonymous):
what is have so far ir 100=1/2x times 10z
OpenStudy (anonymous):
I *
OpenStudy (anonymous):
@Regina.D gorv will help you here.. :)
OpenStudy (anonymous):
Thank you gorv
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OpenStudy (gorv):
second number =y
OpenStudy (anonymous):
okay im using x and y
OpenStudy (gorv):
\[\frac{ x }{ 2 }+10*y=100\]
OpenStudy (gorv):
subtarct x/2 both side
OpenStudy (anonymous):
okay i subtracted it
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OpenStudy (gorv):
10y=100-x/2
OpenStudy (gorv):
divide both side by 10
OpenStudy (gorv):
y=10-x/20
OpenStudy (anonymous):
i wrote that
OpenStudy (gorv):
so we got the value of y
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OpenStudy (gorv):
so now their product
OpenStudy (anonymous):
so now that we have the y value we need x right? since the problem asks for 2 numbers
OpenStudy (gorv):
no x we will keep and replace y with what we got
OpenStudy (anonymous):
oh
OpenStudy (gorv):
product= x*(10-x/20)
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OpenStudy (gorv):
\[=10x-\frac{ x^2 }{ 20 }\]
OpenStudy (gorv):
we have to maximize it
OpenStudy (anonymous):
how do we maximize it?
OpenStudy (gorv):
using differentiation
OpenStudy (gorv):
on differentiation
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OpenStudy (gorv):
=10-2*x/20
OpenStudy (anonymous):
oh god i dont know how to do that
OpenStudy (anonymous):
You can also maximize it by stretching it from both the sides.. :P
OpenStudy (anonymous):
my professor is an idiot
OpenStudy (gorv):
u know how to do differentiation
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OpenStudy (anonymous):
i dont we werent taught it yet which is why im so confused with this problem
OpenStudy (anonymous):
This topic of maximize and minimize comes under Differentiation part...
OpenStudy (gorv):
okk..u know anything about differentiation
OpenStudy (anonymous):
nothing at all
OpenStudy (anonymous):
i just started pre calc
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OpenStudy (gorv):
wait
OpenStudy (anonymous):
May be there is some other method without using differentiation.. :(
OpenStudy (anonymous):
that is why i'm here...because i need help
OpenStudy (gorv):
we can do it using quadratic 's graph but i know that ..but i had prob that i cant make u understand that
OpenStudy (gorv):
@ganeshie8 @hartnn plzz help here..
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
its not that hard of a problem..
OpenStudy (anonymous):
i;m just stupid in math
OpenStudy (anonymous):
but you guys will solve it for sure
OpenStudy (anonymous):
....................................
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OpenStudy (anonymous):
alright you guys are all idiots lmao
OpenStudy (anonymous):
see ya
OpenStudy (anonymous):
We all are idiots here.. :) It is a site for idiots, that's why I think you came here.. :P
OpenStudy (gorv):
@amistre64
OpenStudy (anonymous):
May I try now??
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OpenStudy (gorv):
loll if u know u can
OpenStudy (anonymous):
Let us wait and see what amistre has got in his pocket.. :)
OpenStudy (amistre64):
Find two numbers
define the 2 numbers as: x and y
whose product is a maximum
xy is largest when ...
when the sum of half the first number
x/2
and ten times the second number
10y
is 100
x/2 + 10y = 100
OpenStudy (anonymous):
Simply find x and y?? :P
OpenStudy (amistre64):
all i did was summaraize gorvs procees i believe
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OpenStudy (gorv):
no after that..how we will maximise
OpenStudy (amistre64):
well, with substitution we get a quadratic ....
OpenStudy (gorv):
bcozz the asker havent done differentiation
OpenStudy (gorv):
yeah with quadratic we will do thta what i said
OpenStudy (amistre64):
a vertex is gone over in algebra
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OpenStudy (gorv):
but i cant guide him/her so asked for your assistance
OpenStudy (gorv):
i m weak in qudratic graph having max and min prob
OpenStudy (anonymous):
Somewhere I read, that for quadratic equation's product to be maximum then it is maximum when :
\(x = \frac{-b}{2a}\)
OpenStudy (amistre64):
x/2 + 10y = 100
solve for x (or y, im doing x)
x = 200 - 20y
sub into f = xy
f = (200-20y)y
f = 200y -20y^2
plenty of ways to find the vertex
OpenStudy (amistre64):
x and y in my case are just numbers, not necessarily axis names
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OpenStudy (anonymous):
I mean when product is to maximum, then maximum occurs when :
\[x = \frac{-b}{2a}\]
OpenStudy (amistre64):
what part of this is the asker having difficulty with ?
OpenStudy (anonymous):
For him or her, it is done upto Product.. after that............
OpenStudy (anonymous):
\[P = x y =10x-\frac{ x^2 }{ 20 }\]
OpenStudy (amistre64):
my x sub makes a prettier solution process :) but im biased
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OpenStudy (anonymous):
Wait, after that what you want to do??
OpenStudy (anonymous):
You are going to find maxima for f and then all that?? Is that??