Question

Can someone help me differentiate this?

Answer 1

\[3e ^{-3t}(3-2e ^{t})\]

Answer 2

distribute and work the parts, or product rule it

Answer 3

I've tried that (product rule) but not ending up with the required answer according to my solver

Answer 4

hope youre going to show your work :)

Answer 5

So far, using the product rule, I'm stuck at \[3e ^{-3t}(-2e ^{t}) + (3-2e ^{t})(-9e ^{-3t})\]

Answer 6

Haha, of course I am xD

Answer 7

\[3e ^{-3t}(3-2e ^{t})\]
\[3e' ^{-3t}(3-2e ^{t})+3e ^{-3t}(3-2e ^{t})'\]
\[-9e^{-3t}(3-2e ^{t})+3e ^{-3t}(-2e ^{t})\]

Answer 8

expand it all and see what factors

Answer 9

\[-9e^{-3t}(3-2e ^{t})+3e ^{-3t}(-2e ^{t})\]
\[-27e^{-3t}+18e ^{-2t}-6e ^{-2t}\]

Answer 10

-6e^-2t is a factor

Answer 11

combine like terms and yeah

Answer 12

\[-27e^{-3t}+12e ^{-2t}\]
dunno what your trying to get to tho

Answer 13

Oh :O Thanks!

Answer 14

yw