If an airline claims that it loses 5.5 bags a day from a busy airport, what is the probability that on the day you fly the airline will lose:
4 bags,
Less than 3
8 or 9 bags.

Question

If an airline claims that it loses 5.5 bags a day from a busy airport, what is the probability that on the day you fly the airline will lose:
4 bags, 
Less than 3
8 or 9 bags.

amistre64 · Answer

im curious if this is poisson based

amistre64 · Answer

$$P(x)=\frac{e^{-\mu}\mu^x}{x!}$$

anonymous · Answer

a) 0.156 correct?

amistre64 · Answer

im unsure of the cdf,  pretty sure of it, but cant say its correct.

assuming it is then:  e^(-5.5) (5.5)^4/4! = 0.1558  yes

since there is nothing to indicate a normal distribution, this would be my best attempt

anonymous · Answer

Yes, this is probably poisson based.  It's homework stuff.

amistre64 · Answer

yay!!

amistre64 · Answer

the rest is the addition of the required xs

P(0) + P(1) + P(2) = P(x<3)