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find the derivative of the function: y = 1/(5x-7)^7
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\(\bf y=\cfrac{1}{(5x-7)^7}\implies y=(5x-7)^{-7}\) chain rule it
but dont u need to use the quotient rule also?
sure, you could use the quotient rule as well longer way, but yes
how did the power 7 became negative?
\[y = \frac{1}{(5x-7)^7}\] \[y = (5x-7)^{-7}\] Use chain rule now. \[\frac{dy}{dx} = \frac{d((5x-7)^{-7})}{dx} = -7(5x-7)^{-8}.5 = -35(5x-7)\]
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\(\Large a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\)
\[-35(5x - 7)^{-8}\] would that be the answer?
yeap
thank you, god bless
yw
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