Discrete math. Show that (p→q)▼(q→r) and (p^q)→r are logically equivalent. My question is are they considered logically equivalent if the two propositional statements have the same truth tables?
Yes, if two logical expressions have the same truth tables, then the logical expressions are equivalent (and vice versa). This is because the tables represent all of the possible combinations you can think of. It's like proving 2x = x+x to be true by writing out all of the numbers that satisfy that equation.
Thanks Jim!
np
But are they logically equivalent, though?
The truth tables come out the same for the two statements. So they are right?
Well, IF the truth tables are the same, then they must be equivalent. Let me just double check...
▼ is "or" right?
upside down caret is or....how would I type it correctly?
^ ?
It's an 'and', then?
^ is and, and upside ^ is or.
Uhh.. \[\Large (p\rightarrow q) \lor(q\rightarrow r) \iff (p\land q) \rightarrow r\] Is this it?
a letter v would have sufficed haha
Cool thanks. I got it solved.
Equivalent? Because if it's an 'or', they may not be...
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