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integrate dx/9+4x^2
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\[\int\limits_{}^{} 9 +4x^2 dx\] Is this what you mean?
First split it up into two integrals added together.
i think 9+4x^2 is in the denominator if so try x= (3/2) tan u
\[\int \frac{dx}{9+4x^2}\] Take 4 common from the denominator to make things easier. \[\frac{1}{4} \int \frac{dx}{\frac{9}{4} + x^2}\] It is helpful here to know that, \[\int \frac{dx}{a^2 + x^2} = \frac{1}{a} \tan^{-1} (\frac{x}{a}) + C\] Can you get the integral now? :)
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