How to calculate or simplify the the integral of ((18(ln(x))^5)/x)dx ?
Then, the property of ln() is that if it's raised to anything, you can take that out in front: ln(x)^2 = 2ln(x) Take it from there...
by parts maybe? let u = ln(x) and dv = 1
\[\int\limits \frac{ 18\left( \ln \left( x \right) \right)^5 }{ x }dx\]
like this?
theres an x under there eh .... then just a u sub seems sufficient
if so, let u = ln(x), du = (1/x) dx
Yes pgpilot326 ! thank you
And how do you integrate an ln function? I can't find a clear definition of it in my book.
\[ln^5(x)\ne ln(x^5)\] so that exponent property doesnt fit
the key to this is in knowing how to take the derivative of the ln function
in this one you don't have to integrate ln(x)
when that becomes clear, it can be seen that the chainrule was applied and it cleans up with the u subsititution
I think I got it. Does it become 18(u)^5 du?
it does :)
Ok thank you all very much!
\[\int\limits \frac{ 18\left( \ln \left( x \right) \right)^5 }{ x }dx=18\int\limits u^5 du=\frac{ 18u^6 }{ 6 }=3u^6 = 3\left( \ln \left( x \right) \right)^6\]
waiting for someone to shime in with the +C
i'm singing it... 1 octave above middle C
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