This graph shows the concentration of the reactant A in the reaction A→B. Determine the average rate of the reaction between 0 and 10 seconds.
0.007 M/s 0.014 M/s 0.86 M/s 0.07 M/s
i know that this one is first order
rate=k[A]
The average rate is simple, just add the individual rates and divide by the time
where do i get the rates
would it be (.86-1)/(10-0) which would give me .014
these are the rates 0.007 M/s 0.014 M/s 0.86 M/s 0.07 M/s is there time associated with them? (i havent opened the file, i dont download word documents off the internet)
its just the graph from react concentration versus time for the first order reaction
yes there are time. so i add all of them up and divide by 10
so, 0.07 M/s was the rate for how long?
i mean, if you have 10 measurements (1 every second), then you divide by 10 seconds. But it doesn't seem like you have 10 measurements
.007 looks like for about 1 second
http://session.masteringchemistry.com/problemAsset/1616822/3/TroAMA3.ch13.p1.jpg
hm what you can do in this scenario is take the end points, then just find the slope.|dw:1413133539485:dw|
so we could use .77-.86 /20-10
well do you need the rate between 0 and 10 seconds or 10 to 20 seconds?
i think the answer is .86
( .86-1) /10-0 .14/10 =.014
yep that looks right.
thank you once more and that was my last question
i got an 98 thank you so much and for the knowledge i can use on the test.
great! no problem, glad i could help
Join our real-time social learning platform and learn together with your friends!