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Let P denote the multiplicative group of positive real numbers. Prove that {1} is the ONLY finite subgroup of P @ikram002p group theory for you. Please help
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sorry i dont think i could help with this
It's ok, friend, hihihi... I still have my T.A in recitation tomorrow. No worried, it 's just homework. :)
If \(H\) were a subgroup of \(P\), and \(x\in H\), \(x\ne 1\), then \(x^n\in H\) for all \(n\in \mathbb{N}\) since subgroups are closed under the group operation. Try to use this to show if you have a finite subgroup, the only element in the subgroup can be 1.
Thanks a lot. I need you check my stuff, please.
group size 3 : take off {0,7,21} , it is {0,7,14,21} belongs to group size 4
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