Question

Consider the area shown below. The curve drawn is x^2 + y^2 = 3, and we have used the notation Dy for \Delta y.

Answer 1

https://webwork.colorado.edu/webwork2_files/tmp/Math2300-Fall-2014//gif/pake3850-4372-setHomework009Section8-Q-1prob2image1.png

Answer 2

i know how to make a reiman sum, but after that for writing an integral, how do you go about finding the bounds

Answer 3

This is quarter of a circle and the radius of the circle is \(\sqrt{3}\).
Limits are x = 0 to x = \(\sqrt{3}\).

Answer 4

\[so its \int\limits_{a}^{b} \sqrt{3-y^2}dy\]

Answer 5

y = 0 to y = \(\sqrt{3}\)

Answer 6

how wouuld you go about setting up an equation to find those? do you just substitute values in...?

Answer 7

The uppermost point on the curve is on the y-axis where x = 0
put x = 0 and find y.

Answer 8

oh then when it hits the x axis y=0 and that gives you sqrt3 for the b