Question

Write the formulas of the compounds formed by Pb4+SO32- and Pb4+PO43-?

Answer 1

\[Pb _{4}+SO _{3}^{2-}\]
\[Pb _{4}+PO _{4}^{3-}\]
Is this correct?

Answer 2

Or Pb\[Pb ^{4+}\]

Answer 3

\[Pb^4\] positive

Answer 4

Oh okay just making sure. This formula will be a synthesis.

Answer 5

You start by combining Pb4+ with SO3. You get PbSO3. Now you have to make the charge 0.

Answer 6

Since your charge is 4+ on Pb and 2- on SO3, you add another SO3. Your final formula will be \[Pb(SO _{3})_{2}\]

Answer 7

The second question is also a synthesis.

\[Pb ^{4+}PO _{4}^{-3}\]
= \[Pb _{3}(PO _{4})_{4}\]

Answer 8

I have a question on the first equation. How come the 2- does not go under the Pb and the 4+ does not go under the SO3?

Answer 9

Because if you use that method you are doubling up what you need. 4 / 2 = 2 2/2 = 1

In the end its the same thing

Answer 10

Oh ok! Thank you so much :)

Answer 11

No problem :)