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Find dy/dx of (1/4)(2^(x))
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\[\frac{ 1 }{ 4 }*2^x=\frac{1 }{ 4 }*\frac{ d 2^x}{ dx}\]
=(2^x *ln2)/4
If you're not familiar with the formula for the derivative, it can always be derived: \[\begin{align*} \frac{1}{4}2^x&=\frac{2^x}{2^2}\\\\ &=2^{x-2}\\\\ &=e^{\ln2^{x-2}}\\\\ &=e^{(x-2)\ln2}\\\\ \frac{d}{dx}\left[\cdots\right]&=\ln2~e^{(x-2)\ln2}\\\\ &=\ln2~e^{\ln2^{x-2}}\\\\ &=\ln2~2^{x-2}\\\\ &=\frac{\ln2}{4}~2^x\\\\ &=\frac{\ln2}{4}~2^x \end{align*}\]
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