Question

>n< Halp.
Expand from vertex to standard.
y-2=-3(x+4)^2

>.< I expanded it, and ended up cancelling my x's... I ended up with y=-3x^2+14..... Not only is that not standard form, but I know that my answer is supposed to be y=-3x^2-24x-46 >n<

Answer 1

well just expand what's the problem here?

Answer 2

The problem is y-2=-3(x+4)^2
I expanded it to y-2=-3(x+2)(x+2)
And it cancelled out my x...

Answer 3

oh i see so missed something when you expanded
why x term disappear? shouldn't be that way

Answer 4

first of all that's not true
(x+4)^2=(x+4)(x+4)

Answer 5

but even so i don't think you x's will cancel even with that mistake
but the answer will turn to be wrong since you use a wrong expansion

Answer 6

There's a...... Different expansion? O.o

Answer 7

No there isn'tNo there isn't
what you did is wrong (a+b)^2=(a+b)(a+b)
see here i haven't changed my a and b?
you problem is that you are thinking about
a^2-b^2=(a+b)(a-b) although there totally different
but you thought about something like this
x^2-9=(x+3)(x-3)

what you did is wrong (a+b)^2=(a+b)(a+b)
see here i haven't changed my a and b?
you problem is that you are thinking about
a^2-b^2=(a+b)(a-b) although there totally different
but you thought about something like this
x^2-9=(x+3)(x-3)

Answer 8

hehe OP is going crazy lol

Answer 9

Sorry for the repeatition open study got stuck

Answer 10

That's alright.
So, Like yhu said, if I expand, it should look like y-2=-3(x+4)(x+4) Right?

Answer 11

correct
now distribute that parenthesis

Answer 12

\[y-2=(-3-12)(x+4)\]
... Right?

Answer 13

Oops I forgot my x... That should say (-3x-12)*

Answer 14

yeah! continue

Answer 15

\[y-2=-3x ^{2}-24x-48\]
>O<; Oh my god.
Thank yhu. ^u^