The given point is on the graph of y=f(x). Find a point on the graph of y=g(x). g(x)=f(x-1)+3; (6,16)
since (6,16) is on the graph of y = f(x), we know that f(6) = 16
compare f(x-1) to f(6). What must x be equal to?
ie, f(x-1) = f(6) ----> x = ???
@jim_thompson5910 okay so x=5, f(5-1)+3 = 7 so how to I find the y cordinate?
oh I got it (7,19) very very VERY confusing tho!
(7,19) is close, but not correct
x = 7 g(x)=f(x-1)+3 g(7)=f(7-1)+3 g(7)=f(6)+3 g(7)=16+3 g(7)=19 nvm I misread lol. So yeah, (7,19) is on g(x)
lol! I have another similar question... I will try on my own real quick.
ok post the question and what you get
@jim_thompson5910 g(x)=1/4f(x);(-4,20) I got (-1,5) and I know its wrong because answer keys says its (-4,5)
(-4,20) means f(-4) = 20
plug x = -4 into g(x) g(x)=1/4f(x) g(-4)=1/4f(-4) g(-4)=1/4*(20) g(-4)=5
you're only taking 1/4 of the y coordinate while you leave the x coordinate alone
OOOH!! I see.. thank you so much!!! :) I have a test tmrw I really appreciate your help!
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