Using the standard enthalpies of formation, what is the standard enthalpy of reaction?

CO(g) + H2O --- CO2(g) + H2(g)
CO2= -393.5
CO= -110.5
H2= 0
H2O= -285.8

I keep getting 2.8 put it says the answer is wrong

Question

Using the standard enthalpies of formation, what is the standard enthalpy of reaction?

CO(g) + H2O ---> CO2(g) + H2(g)
CO2= -393.5
CO= -110.5
H2= 0 
H2O= -285.8


I keep getting 2.8 put it says the answer is wrong

aaronq · Answer

$\Delta H=(-393.5)-((-285.8)+(-393.5))$

$\Delta H=(-393.5)-(-679.3)$

$\Delta H=-393.5+679.3)=285.8$

anonymous · Answer

my hw saying its incorrect though

aaronq · Answer

lol oh i copied down the value for CO incorrectly 


$\Delta H=(-393.5)-((-110.5)+(-285.8))=2.8 $

i get the same thing.


were you given those values or did you look them up?

anonymous · Answer

i looked them up
from my text book

anonymous · Answer

but thanks anyways

aaronq · Answer

for water, was it liquid or gas?

anonymous · Answer

i made the mistake by putting liquids instead of gas oopppps lol thanks

aaronq · Answer

hah there we go. no probs