Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Will Give Medal To anyone who answers!

OpenStudy (anonymous):

The volume of a rectangular box is (x3 - 7x2 - 9x + 63) cubic units. Determine the dimensions of the rectangular box by factoring the volume expression completely. Show your work.

OpenStudy (anonymous):

So far this all I have x^3-7x^2-9x+63 x^2(x-7)-9(x-7) (x^2-9)(x-7)

OpenStudy (anonymous):

@hedyeh99

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

Not bad, you're nearly done now use difference of squares for (x^2-9)

OpenStudy (anonymous):

how would I do that

OpenStudy (anonymous):

Difference of square is (a+b)(a-b) = a^2-b^2 so you have (x^2-9) which is the same thing as (x^2-3^2) right? So what can we conclude :)

OpenStudy (anonymous):

Umm, Im not sure, sorry Im not that great at this

OpenStudy (anonymous):

\[(a^2-b^2) = (a+b)(a-b) \] this is what we get when we foil the left side out right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

So, now we back track \[(x^2-9) \implies (x^2-3^2) \implies (x-3)(x+3)\] x is your a, 3 is your b :)

OpenStudy (anonymous):

ahh okay, i see

OpenStudy (anonymous):

Right on, so your final answer now is (x-3)(x+3)(x-7)

OpenStudy (anonymous):

That would be the answer to the question? Or would it need to be simplified further? @iambatman

OpenStudy (anonymous):

Well now you would need the roots, which you just said each factor = 0, and solve for x. You'll get, 3,-3, and 7.

OpenStudy (anonymous):

So, those would be my answers to the whole question?

OpenStudy (anonymous):

Yeah since they want the dimensions those are it.

OpenStudy (anonymous):

Okay, Thank you very much :)

OpenStudy (anonymous):

Np ^.^

OpenStudy (anonymous):

Btw if you're interested in reading about difference of squares here is a link: http://www.regentsprep.org/regents/math/algebra/AV6/Lfactps.htm

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!