Will give medals! Help! Draw 2 cards in order. What is the probability of getting a Jack then a red 10?
How many Jacks are there in a standard 52 card pack?
4
Right. So the probability of drawing a Jack first is 4/52. If a Jack has been drawn first: 1. How many cards remain? 2. How many red 10 cards remain in the pack?
there would be 51 left over, and then there are 2 red 10 cards
Right again! So the probability of drawing a red 10 on the second draw is 2/51. Therefore the required probability is given by: \[\large \frac{4\times2}{52\times51}=you\ can\ calculate\]
.003% ?
Yes. Or, the exact probability is 2/663.
my book says the correct answer is .00603 but i don't get how they got that
Actually you should not put the percentage sign after your result.
okay
im not sure that the answer is .00301
thanks for trying to help
Perhaps I misinterpreted the question. I took it that the order of selection was Jack first, then red 10 second. But if the order of selection can be reversed, then the required probability will be 4/663.
perfect, that maps out to be .00603 (as the book states). but how did we get 4/663?
The probability of the event 'Jack first then red 10 second' is 2/662. The probability of the event 'red 10 first and Jack second' is also 2/663. The two events are mutually exclusive (the events cannot occur together) therefore the probability of one event or the other is the sum of the two values of probability.
mind = blown. i would have never gotten that. thank you so muuh
You're welcome :)
got time for one more? :D
jk if you dont want to. this stuff is tough lol
Can you please post as a new question. Thanks.
sure
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