Question

PLEASE HELP DERIVITIVE Q. last resort
https://docs.google.com/viewer?a=v&pid=sites&srcid=ZGVmYXVsdGRvbWFpbnxtYmFybmVzbWF0aHxneDoyZGVhMGUyNTY3Y2YxMzc1 please follow the link and can you tell me what you would get for 27? the very first problem? I got b but friends have gotten c and im not sure who to believe. This determines whether I get a c or a b in the class.

Answer 1

@loser66 please please help if you can. just want to check my answer.

Answer 2

where is your answer?

Answer 3

sorry what do you mean where? I think itsb

Answer 4

the answer should be b since the derivative of tan(x) is sec^2(x)

Answer 5

are you sure? and what about number 4 at the bottom of the first page.

Answer 6

have you tried plugging in the point to see whether it meets the criteria for it to be true?

x= 3 but x^2 = 9 and 9 < 3

Answer 7

nope, tan' = sec^2 but
dy/dx = tan
so to get dy, you must
dy = tan dx
take integral both sides to get y = ln|sec| +C

Answer 8

That's just my guess, :P

Answer 9

@Jhannybean im talking about the 27 on the first page.

Answer 10

the answer should be -2sin(2x) but since its not one of the answer im guessing it would be e

Answer 11

@Loser66 makes sense

Answer 12

Don't get me?? @zmanlane

Answer 13

loser u sure about it? and what about 4 at the bottom of the same page 27 was on? I got c but my friedns are getting E soim not too sure.

Answer 14

\[\dfrac{dy}{dx}= tanx\\dy = tanx dx\]
then take integral to get C, sure !!! :)

Answer 15

\[\frac{dy}{dx}= cos(2x)\]\[\ dy = \cos(2x)dx\]\[\int{dy} =\int{cos(2x)dx}\]\[\ y = \int\cos(2x)dx\]

Answer 16

Just solve for that and you'll find your answer :)

Answer 17

@Jhannybean reread the problem, it say dy/dx = tan x , not as you wrote

Answer 18

@Loser66 that's #4.

Answer 19

I don't see a #27 at the bottom of the first page :|

"zmanlane
@Jhannybean im talking about the 27 on the first page. "

Answer 20

hmmmmm, you should post one by one. or label it correctly, don't mix them
Now, again, what is it?? type it out

Answer 21

here,

Answer 22

dy/dx=cos(2x)

Answer 23

Yeah I just helped you solve that one :P

Answer 24

but whats the answer @Jhannybean? I don't get what do do after you left off. like how to solve.

Answer 25

@Jhannybean ?

Answer 26

So you have \[\int \cos(2x)dx\] let u = 2x and du = 2dx. You get \(\large \int cos(u)du\) Do you know what the integral of cos(u) is?

Answer 27

I haven't done integrals yet. @Jhannybean

Answer 28

Hmm, have you done antiderivatives?

Answer 29

Woops :3 you get \(\Large\rm \frac{1}{2}\int\cos(u)du\)

Answer 30

You haven't done integrals yet? :O
What is this worksheet about then?
Just practice?