From the equation of the line, determine the value of μk.
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I don't see a mu anywhere. Does that stand for something? :o
I think it does but im not sure what
Maybe somehow we can guess the meaning. What have you been talking about in class (or what has the instructor been talking about in class)?
forces and friction
here's how the problem starts. Your assignment in lab is to measure the coefficient of kinetic friction between a 350-g block and a smooth metal table. To do so, you decide to launch the block at various speeds and measure how far it slides.
@freckles
http://www.pstcc.edu/departments/natural_behavioral_sciences/Web%20Physics/Experiment%2005web.htm then I think kinetic friction is muk
how would i solve it with that equation?
oh I was just showing where muk has been used before as kinetic friction just verifying what it means also I'm still trying to go over this subject
do you know if we need to integrate?
Well I think the acceleration is given by the slope of that line
so we have acceleration and ...
i dont think we integrate
https://www.physicsforums.com/threads/finding-the-kinetic-friction-force-using-mass-and-acceleration.584159/ This is what I'm reading now.
we are given acceleration and weight
this looks like it gives us a recipe to get the muk
so its .350 kg * 4.8217 ?
well there is one step further to go
Fkf = µkFn does equation look familiar we want to solve for muk divide both sides by Fn
I don't know how to find Fn do you?
no
but on the link you posted it says after multiplying those two above we divide it by the weight in N of the block, what it the weight?
Well that is what I'm talking about I don't know what Fn is
me neither
is it normal force
yes but I don't know if i can actually help you anymore I can identify the acceleration from that line but that is about it
sorry i'm not more knowledgeable in this area
whats the acceleration
acceleration was the slope of the line
I knew that because velocity was the line in from calculus we learn the derivative of velocity will give us acceleration
so its 4.8217
If that graph is showing an equation for velocity yes
which I think it is
so we dont know how to find kinetic friction
so it wouldn't be .350 kg*4.8217/.350*9.8
it might be .35 kg *4.8217/9.8 is 9.8 is the normal N I guess And if the line that was actually given was the line for velocity
But @mony01 This isn't my expertise. I was hoping for a calculus question when I stumble into problem. :p I didn't know what muk was at the beginning.
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