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Mathematics 8 Online
OpenStudy (mony01):

From the equation of the line, determine the value of μk.

OpenStudy (mony01):

OpenStudy (adamaero):

@zepdrix @iambatman @Compassionate @goformit100 @bibby @austinL

OpenStudy (adamaero):

@gabylovesyou @calculusxy @firejay5 @HelpBlahBlahBlah

zepdrix (zepdrix):

I don't see a mu anywhere. Does that stand for something? :o

OpenStudy (mony01):

I think it does but im not sure what

OpenStudy (freckles):

Maybe somehow we can guess the meaning. What have you been talking about in class (or what has the instructor been talking about in class)?

OpenStudy (mony01):

forces and friction

OpenStudy (mony01):

here's how the problem starts. Your assignment in lab is to measure the coefficient of kinetic friction between a 350-g block and a smooth metal table. To do so, you decide to launch the block at various speeds and measure how far it slides.

OpenStudy (mony01):

@freckles

OpenStudy (freckles):

http://www.pstcc.edu/departments/natural_behavioral_sciences/Web%20Physics/Experiment%2005web.htm then I think kinetic friction is muk

OpenStudy (mony01):

how would i solve it with that equation?

OpenStudy (freckles):

oh I was just showing where muk has been used before as kinetic friction just verifying what it means also I'm still trying to go over this subject

OpenStudy (freckles):

do you know if we need to integrate?

OpenStudy (freckles):

Well I think the acceleration is given by the slope of that line

OpenStudy (freckles):

so we have acceleration and ...

OpenStudy (mony01):

i dont think we integrate

OpenStudy (freckles):

we are given acceleration and weight

OpenStudy (freckles):

this looks like it gives us a recipe to get the muk

OpenStudy (mony01):

so its .350 kg * 4.8217 ?

OpenStudy (freckles):

well there is one step further to go

OpenStudy (freckles):

Fkf = µkFn does equation look familiar we want to solve for muk divide both sides by Fn

OpenStudy (freckles):

I don't know how to find Fn do you?

OpenStudy (mony01):

no

OpenStudy (mony01):

but on the link you posted it says after multiplying those two above we divide it by the weight in N of the block, what it the weight?

OpenStudy (freckles):

Well that is what I'm talking about I don't know what Fn is

OpenStudy (mony01):

me neither

OpenStudy (mony01):

is it normal force

OpenStudy (freckles):

yes but I don't know if i can actually help you anymore I can identify the acceleration from that line but that is about it

OpenStudy (freckles):

sorry i'm not more knowledgeable in this area

OpenStudy (mony01):

whats the acceleration

OpenStudy (freckles):

acceleration was the slope of the line

OpenStudy (freckles):

I knew that because velocity was the line in from calculus we learn the derivative of velocity will give us acceleration

OpenStudy (mony01):

so its 4.8217

OpenStudy (freckles):

If that graph is showing an equation for velocity yes

OpenStudy (freckles):

which I think it is

OpenStudy (mony01):

so we dont know how to find kinetic friction

OpenStudy (mony01):

so it wouldn't be .350 kg*4.8217/.350*9.8

OpenStudy (freckles):

it might be .35 kg *4.8217/9.8 is 9.8 is the normal N I guess And if the line that was actually given was the line for velocity

OpenStudy (freckles):

But @mony01 This isn't my expertise. I was hoping for a calculus question when I stumble into problem. :p I didn't know what muk was at the beginning.

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