For tax reasons, I need to create a rectangular vegetable patch with an area of exactly 162 sq. ft. The fencing for the east and west sides costs $4 per foot, and the fencing for the north and south sides costs only $2 per foot. What are the dimensions of the vegetable patch with the least expensive fence? north and south sides? east and west sides?
plz i need help i don't know what to do
okay give me a sec
thank you I'm so lost
4 dollar per foot on east and west side. 2 dollar per foot on north and south side. the least expensive fense would be the LEAST use of east and west fence, thus, you need to MAXIMIZE fence on north and south side... Now think, what are two numbers that can multiply to 50? 1x50 2x25 5x10 Remember, we want the fence to cost as little as possible. So the larger number can be reasonably the north and south side while smaller side is the east and west. If you look at the 3 dimensions i provide, 1x50 is the best possible answer. Though not ask for... since the fence has four sides, you'd find the circumference of the 1x50 dimension. The total cost: north: 50x$2 east: 1x$4 south: 50x$2 west: 1x$4 -------------- sum is $208
East/west side is 10 feet North/south side is 20 feet to make this easier
it says its wrong.....
I might of did something wrong. Sorry, let me see if i can get some people.
ok thank you!
@aum @jhonyy9
They will probably come eventually but, I have to go. Im sorry. Heres a medal for you. :)
it says it is wrong what is wrong?
\[xy=162, 8x+4y=C\] you want to minimize C
since \[xy=162\] you know \[y=\frac{162}{x}\]
the answer he provided me was wrong yes
plug it in and get \[C(x)=8x+\frac{648}{x}\] this is a calculus problem right?
yes it is
there is your function, domain is \(x>0\) take the derivative, find the critical point etc
dude please i have no idea what your talking about
i don't know what a critical point is
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