Find the exact length of the curve. y = ln(sec x), 0 ≤ x ≤ π/4
\[\int\limits_{0}^{\frac{\pi}{4}}\sqrt{1+(y')^2} dx \]
do you recognize this formula?
Yes! I'm just stuck trying to integrate \[\int\limits_{0}^{\pi/4} \sqrt{1+\tan^2} dx\]
what is 1+tan^2(x) think of an identity
Pythagorean identity
these problems cooked to within an inch of their life think of all the effort it took to make a problem where you could take the derivative, square it, add 1, take the square root, and then come up with something integrable i tried it once, it took over half an hour maybe over an hour
lol That is why I give up and only gave problems from the book as test questions
i know right? i was kind of proud of myself when i was done
Oh sec^2(x)!
yeppie!
and sec is positive on the interval 0 to pi/4 so sqrt(sec^2(x))=sec(x)
Thank you so much! :)
np
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