Question

1-cos^2(theta)/1+cos^2(theta)+2cos^2(theta) simplify

Answer 1

\[\left(\frac{1-\cot^2\left(\theta\right)}{1+\cot^2\left(\theta\right)}\right)+2\cos^2\left(\theta\right)\]

Answer 2

\[1 + \cot^2(x) = cosec^2(x)\]

Answer 3

\[\frac{1- \cot^2(x)}{cosec^2(x)} + \cos^2(x) \implies \frac{1}{cosec^2(x)} - \frac{\cot^2(x)}{cosec^2(x)} + \cos^2(x)\]

Answer 4

\(\large \frac{1}{cosec^2(x)}\) = ??

Answer 5

so simplified it just equals 1/ cosec^2 (x)

Answer 6

??

Answer 7

dont have to solve jsut simplify

Answer 8

I ask you something.. Answer that..

Answer 9

Simplifying means we need to solve it and simplify more, in its simplest form we have to represent it..

Answer 10

1/cosec = sin

Answer 11

so 1 / csc^2 = sin^2?

Answer 12

Yes, so:

\[\sin^2(x) - \cot^2(x) \cdot \sin^2(x) + \cos^2(x)\]

Answer 13

Now, \(sin^2(x) + cos^2(x)\) = ??

Answer 14

1?

Answer 15

Yep:

it becomes :\[\implies 1 - \cot^2(x) \cdot \sin^2(x)\]

Answer 16

Now, do you know any formula for \(cot(x)\) in terms of \(sin(x)\) and \(cos(x)\) ??

Answer 17

1/tan = cot

Answer 18

so 1/sin/cos

Answer 19

or simply cos/sin Okay??

Answer 20

ah yea simplfied you right

Answer 21

\[\cot(x) = \frac{\cos(x)}{\sin(x)}\]

Answer 22

Put it there..

Answer 23

\[\implies 1 - \frac{\cos^2(x)}{\sin^2(x)} \cdot \sin^2(x)\]

Answer 24

\[\implies 1 - \frac{\cos^2(x)}{\cancel{\sin^2(x)}} \cdot \cancel{\sin^2(x)} \implies 1 - \cos^2(x) = ??\]

Answer 25

sin^2(x)

Answer 26

yep..

Good..!!! :)

Answer 27

you're a lifesaver!

Answer 28

Really?? But OS is giving title of "Champion" to me... :P

Just kidding..!!

Actually, I like Trigonometry, it is my favorite topic from MATHS.. :)

Answer 29

Haha! Ya math is kinda fuzzy for me taht's my im chosing to major in chemistry! lol

Answer 30

oooo

Answer 31

what about that 2cos^2(x) at end