Can i get a little help please? not sure what to do here..... Calculate a Riemann sum S3,3 on the square R=[0,3]×[0,3] for the function g(x,y)=f(x,y)+2. The contour plot of f(x,y) is shown in Figure 4. Choose sample points and use the plot to find the values of f(x,y) at these points. Use the values of f(x,y) to evaluate g(x,y) accordingly.
@ganeshie8, can you please help me again?
Notice that each square grid has an area of \(\Delta A = 1\)
You choose the sample points from \(P_{11}\) to \(\large P_{33}\) one in each grid
\[\large S_{3,3} = \sum \limits_{i=1}^3\sum\limits_{j=1}^3P_{ij}\cdot \Delta A\]
since the area in xy plane is a constant 1 : \[\large S_{3,3} = \sum \limits_{i=1}^3\sum\limits_{j=1}^3P_{ij}\]
just find all the 9 values and add them up
trying to remember reimann sum. it's been a year since calc 1. i know you add up all the amounts and divide by the number of sections....
there is nothing to divide here, its more simpler than you think it is
we're just slicing a solid into pieces of square base of side 1, finding each piece volume and adding up
http://math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/vcalc/255doub/plot4.gif
the volume of each slice is base area times height, since the base is just an unit square, the volume simply equals the height (or value of the function g(x,y) )
so how do we determine the height with no points?
none of the point values are very clear
Look at the given contour plot, \(\large P_{11} = f(x,y) + 2 = 2 + 2 = 4\) \(\large P_{12} = f(x,y) + 2 = 3 + 2 = 5\) \(\large P_{13} = f(x,y) + 2 = 5 + 2 = 7\)
the value of a function stays same on a level curve
oh. i'm blind. didn't see the 2 next to the points. lol.
:) from that you can assume that the level curves are incrasing their value as you move out
can you figure out remainign 6 values ?
wait, P (1,1) is 2 and P (2,1) is 3
wrong, P(1,1) is 2+2 and P(2,1) is 3+2
the value is for the whole curve
don't forget that the given contour plot is of f(x,y) but you want the riemann sum for g(x,y)
so you need to add +2 to each value
i have P(1,1)=4. P (1,2)=5, P (2,1)=5, P(2,2)=5. P(3,1)=6, P(1,3)=7 and P (3,3) = 10. right?
er
wrong
check P(2,2) again
P(3,3) is 12.
P(2,3)=8, P(3,2)=9, P(3,1)=6. etc. P(2,2) = 6...oops
looks good, add them all up and you're done
so just add up all those numbers? 4+5+5+6+6+7+8+9+12?
62. correct answer! yay!!
good job!
kinda wish webwork gave hints.....are you a teacher, ganeshie? you're so very helpful.
actually explain things rather than just giving me an answer. i appreciate that.
np, yw :) calc3 is fun indeed! you will never be needing these riemann sums again.. calc3 is all about line integrals(work) and surface integrals(flux)
thanks, this is my second attempt to do calc 3.
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