Question

Solve by substitution.

y = x − 1
2x − 3 y = negative-1











Infinite solutions










(4, 3)










(0, 0)










(3, 4)

@igreen

Answer 1

\(y = x − 1 \)
\(2x − 3 y = -1\)

Input x - 1 for y in the second equation:

\(2x − 3 y = -1\)

\(2x - 3(x - 1) = -1\)

Distribute 3 into the parenthesis:

\(2x - 3x - 3 = -1\)

Subtract:

\(-x - 3 = -1\)

Add 3 to both sides:

\(-x = 2\)

Multiply -1 to both sides:

\(x = -2\)

Answer 2

Now that we have the x value, we can plug it in any of the equations to find the y-value.

\(y = x - 1\)

Plug in -2:

\(y = -2 - 1\)

Subtract:

\(y = -3\)

Answer 3

oh someone beat us here

Answer 4

UGH

Answer 5

Okay, I did something wrong..xD

Answer 6

yea

Answer 7

@R-Y-P