Ask your own question, for FREE!
Chemistry 15 Online
OpenStudy (anonymous):

Write out the complete electron configuration for the element P, atomic number 15 and explain how you would place the last few electrons in orbitals. What rule would apply?

OpenStudy (anonymous):

Can u explain it to me please

OpenStudy (cwrw238):

1s2 2s2 2p6 3s2 3p3 - the s orbitals have max occupancy of 2 electrons and the p have 6 the last 3p orbital contains 3 electrons in phosphorus atom

OpenStudy (cwrw238):

Phosphurus is in Group 5 of Periodic Tables and has 5 electrons in its outermost shell. 2 are in 3s orbital so there are 3 left to go into the 3p orbital

OpenStudy (anonymous):

2,8,5

OpenStudy (anonymous):

this enables the configuration to have the complete number of electrons required. the max no. of electrons in the first shell is 2 and the second is 8 for the third shell the max is 18 but since the valence for atoms with less electrons ranges from +1 to -3 http://en.wikipedia.org/wiki/Valence_(chemistry) hope it helps :D

OpenStudy (anonymous):

Thanks @ramal @cwrw238

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!