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Physics 13 Online
OpenStudy (anonymous):

Can someone please help me determine the displacement of a plane that experiences uniform acceleration from 66m/s to 88m/s in 12s?

OpenStudy (anonymous):

S = ut + 0.5*a*t^2 do you know how to use this equation?

OpenStudy (anonymous):

no im sorry, can you help me?

OpenStudy (anonymous):

like what do the variables 's' and "u' stand for?

OpenStudy (anonymous):

S is the physics unit for distance traveled and U is the initial "starting" velocity. so the distance traveled = 66 * 12 + 0.5 * a * 12^2 Do you know how to calculate a (which is acceleration)?

OpenStudy (anonymous):

its the initial velocity subtracted from the final velocity over the time so i got 22/12

OpenStudy (anonymous):

and i assume you plug that into the 'a' space in the equation

OpenStudy (anonymous):

Note that you use total time taken (except when there are two different) parts of the question where you must consider acceleration and deceleration for example in which case you still just use the total time taken but for that part of the scenario.

OpenStudy (anonymous):

Yep!

OpenStudy (anonymous):

Thank you so much, this really helped! :)

OpenStudy (anonymous):

I hope I am correct in everything but that should be spot on! You're welcome :)

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