NEED HELP!! Which of the following quantum number combinations is not allowed in an atom? n = 2, l = 0, m subscript l = 0 n = 3, l = 2, m subscript l = -1 n = 6, l = 5, m subscript l = -4 n = 1, l = 0, m subscript l = 1 @ganeshie8
are you familiar with the quantum number rules? http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch6/quantum.html#rules Rules Governing the Allowed Combinations of Quantum Numbers The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The principal quantum number (n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on. The angular quantum number (l) can be any integer between 0 and n - 1. If n = 3, for example, l can be either 0=s, 1=p, or 2=d. The magnetic quantum number (m) can be any integer between -l and +l. If l = 2, m can be either -2, -1, 0, +1, or +2.
Im so lost in Chemistry its crazy haha but would it be A?
@Cuanchi
Yea you are lost!! I dont think that A is the correct answer.
D?!
That has better chances!! I would go for that, did you got it or just guessed
well i ruled out B and C so it had to be A or D
good approach!
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