Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Answer 1

y = 4/3x + 8

y = 4/3x + 3

y = -3/4x + 8

y = -3/4x + 3

Answer 2

get it into point intercept form (y=mx+b)
3y=4x+12
y=\(\frac{4}{3}\)x+4

our line has the same slope, but passes through -3,4

we can use the point slope form equation for that. \(y-y_1=m(x-x_1)\)

Answer 3

do you need a little push?

Answer 4

The correct answer is
y=4/3 x +7

Answer 5

yes

Answer 6

I think u should check your option of question

Answer 7

thats not an option

Answer 8

\(y_1\) is the y we want. \(x_1\) is the x we want
\(y-y_1=m(x-x_1)\)
m=\(\huge \frac{4}{3}\)

\(y_1=4 | x_1=-3\)

Answer 9

Then this is correct answer either there is mistake or there is some other point I means (-3,5) is this point in your book question check it.

Answer 10

so let's plug that stuff into the equation
y-4=\(\frac{4}{3}\)(x--3)
\(\huge y-4=\frac{4}{3}x-\cancel{3}*\frac{4}{\cancel{3}}\)

Answer 11

uh

Answer 12

wait do i cross it off both sides

Answer 13

yeah, you sure it's (-3, 4).?

Answer 14

yeah thats what it said im confused by it

Answer 15

no, not yet. that was just for \(\frac{4}{3}*3\)

Answer 16

oh

Answer 17

god I'm so fucking stupid

Answer 18

\[\large y-4=\frac{4}{3}(x--3)\]\[\large y-4=\frac{4}{3}(x+3)\]

Answer 19

do you think the question was written wrong or something

Answer 20

\[\large y-4=\frac{4}{3}x+\frac{4}{\cancel{3}}*\cancel{3})\]y-4=\(\frac{4}{3}x+4\)

Answer 21

y=4/3x+8

Answer 22

no, I'm just all over the place rn lol

Answer 23

oh so y=4/3x+8 was the right answer????

Answer 24

yeah

Answer 25

do you see how we got there though?

Answer 26

Your work helped me understnd these typeof problems alot better

Answer 27

noice, noice.
to reiterate.
step 1: get into point intercept form
step 2: plug into point slope form