Question

What volume of carbon dioxide measured at STP will be formed by the reaction of 1.42 moles of oxygen with 0.900 moles of ethyl alcohol, CH3CH2OH?
A. 40.2 L
B. 21.2 L
C. 31.8L
D. 47.7 L
E. 0.947 L

Answer 1

1. Write and balance the combustion equation for CH3CH2OH

2. calculate the amount of CO2 produced by each of the reactants amounts given in the problem. The smallest amount of CO2 produced is the one that is produced by the limiting reactant.

3. convert the the moles of CO2 produced by the limiting reactant to liters of gas considering that 1 mole of any gas at STP conditions will have a volume equal to 22.4 L

Answer 2

What would the balanced equation be?

Answer 3

do you know how to balance this equation?

CH3CH2OH+O2 -> CO2+ H2O

Answer 4

CH3CH2OH + 3O2 --> 2CO2 + 3H2O

Answer 5

yes
now calculate how much CO2 you can produce with 1.42 moles of O2 and how many with 0.9 of ethyl alcohol

1.42 moles O2 x 2 molCO2 /3mol O2

Answer 6

I got B for the answer.

Answer 7

yes!!