identify all of the following solutions of square root of x plus 14 end root plus 2 equals x the possible answers are x = -6 x = 1 x = -6 and x = 1 None of the above @StudyGurl14
\[\sqrt{x+14}+2=x\] \[\sqrt{x+14}=x-2\] \[x+14=(x-2)^2\] \[x +14 = x^2-4x+4\] \[0=x^2-5x-10\] Take the answer choices and plug them in and solve. If they come out to a true statement, that one is answer. If none of the answer choices work, the answer is "None of the above"
I'll do the first one so you can see how to do it: \[x^2-5x-10=0\] \[(-6)^2-5(-6)-10=0\] \[36 +30 -10=0\] \[56\neq0\] So -6 is not a solution. Thus, you can eliminate answer choices A and C
is it none of the above? @StudyGurl14
correct
great! I need help with a few more the next one is which of the following is a solution to 6 square root of x plus 1 equals 24 the possible answers are x = 17 x = 15 x = 5 x = 3
If I help you with this one will you please fan me and write a testimony?
of course! you're helping me so much
Great thanks!
\[6\sqrt{x}+1=24\] Or... \[6\sqrt{x+1}=24\]
is it x=3?
Which equation is it?
oh sorry its the second one
Okay \[6\sqrt{x+1}=24\] \[\sqrt{x+1}=4\] \[x+1=4^2\] Can you do the rest yourself?
yes thank you!
anytime :)
okay two more and I promise ill leave you alone! 1. Simplify 9 fourth root of 10 end root plus 2 cubed root of 10 end root minus 6 fourth root 10 end root 6 cubed root of 10 the possible answers for this one are 3 fourth root of 10 end root 4 cubed root of 10 3 fourth root of 20 end root minus 4 cubed root of 20 negative square root of 10 negative square root of 20
\[9\sqrt[4]{10}+2\sqrt[3]{10}-6\sqrt[4]{10}+6\sqrt[3]{10} \] Like this?
yes! exactly like that
Okay, just combine like terms. the fourth roots are like terms with each other, and the cube roots are like term each other 9 - 6 = 3 and... 2 + 6 = 8 so... \[3\sqrt[4]{10}+8\sqrt[3]{10}\]
great thanks! and the last one is Multiply open parentheses 2 plus 5 square root of 3 close parentheses open parentheses 7 minus square root of 3 and the possible answers are 14 plus 28 square root of 3 14 minus 5 square root 3 negative 1 plus 33 square root of 3 negative 1 plus 37 square root of 3
\[(2+5\sqrt{3})(7-\sqrt{3})\] \[14-2\sqrt{3}+35\sqrt{3}-5(3)\] \[14+33\sqrt{3}-15\] \[-1+33\sqrt{3}\]
thank you so so so so much!
You're so so so so welcome :)
Join our real-time social learning platform and learn together with your friends!