Could someone check my answer for Algebra II, please?
\[\sqrt[7]{x^5}*\sqrt[7]{x^5}\]
I'm gonna take a guess and say it's x^4/9?
Hey, remember that \[\huge \sqrt[n]{x^m} \implies x ^{\frac{ m }{ n }}\]
So if you have \[\huge \sqrt[7]{x^5} \implies x ^{\frac{ 5 }{ 7 }}\]
And if you have to of them, when you multiply by exponents you are essentially adding the exponents :)
\[\huge \sqrt[7]{x^5} \times \sqrt[7]{x^5} \implies x ^{\frac{ 5 }{ 7 }+\frac{ 5 }{ 7 }} \implies x^?\]
Umm, would it be just x? Sorry, Algebra II is VERY new to me!
Wait x^10/7?
Yes :) you're just adding now ^.^
And you can put it in radical form as well if you like which is \[\huge \sqrt[7]{x^{10}}\]
Thanks so much! But that's not a given answer...
What are the given answers?
\[(x^5)^{2/7}\] is also an answer.
\[√x\] \[(x)^(4/9)\] x \[\sqrt[7]{x^3}\]
Which is the same thing
Oh wait that last one is wrong.... here!:
:P
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What was the first answer?
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