Question

NEED HELP FACTORING:
(x+8)^2 - 3

Answer 1

Ok.

Answer 2

I can try.

Answer 3

Is the problem copied correctly, or is there anything missing?

Answer 4

\[(a+b)^2 = a^2+2ab+b^2\]
\[(x+8)^2\]
a = x, b = 8
\[a^2 + 2ab+b^2\]
\[(x)^2+2(x)(8)+(8)^2\]
\[x^2+16x+64\]
Then minus 3
\[x^2+16x+64 - 3 = x^2+16x+61\]

Answer 5

well it says a to factor y=(x+8)^2 - 3

Answer 6

OK. This is how I'd do it.
(x + 8)^2 is the square of x + 8.
3 is the square of \(\sqrt{3} \)
That means you can rewrite this as the difference of two squares:
\((x + 8)^2 - (\sqrt{3})^2\)

Answer 7

The difference of two squares factors like this:
\(a^2 - b^2 = (a + b)(a - b)\)
Now apply this to your problem.

Answer 8

\((x + 8)^2 - (\sqrt{3})^2 = (x + 8 + \sqrt{3})(x + 8 - \sqrt{3} )\)