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Mathematics 15 Online
OpenStudy (anonymous):

MEDAL HELP PLEASE http://gyazo.com/746c18162b0dcbc563c5743166573f60

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

first you need to find the x coordinate of the vertex use the formula x = -b/(2a)

jimthompson5910 (jim_thompson5910):

f(x) = -5x^2 - 20x - 10 is in the form y = ax^2 + bx + c a = -5 b = -20 c = -10

jimthompson5910 (jim_thompson5910):

so you'll plug a = -5 and b = -20 into x = -b/(2a) to get x = ??

OpenStudy (anonymous):

x = -100?

jimthompson5910 (jim_thompson5910):

no you divide, not multiply

jimthompson5910 (jim_thompson5910):

/ means division

OpenStudy (anonymous):

-2

jimthompson5910 (jim_thompson5910):

now plug that into f(x) to get f(-2) = ???

OpenStudy (anonymous):

100- (-40) - 100?

OpenStudy (anonymous):

10*

jimthompson5910 (jim_thompson5910):

so because f(-2) = 10, we know the vertex is the point (-2,10)

jimthompson5910 (jim_thompson5910):

vertex: (h,k) = (-2,10) ----> h = -2 and k = 10

jimthompson5910 (jim_thompson5910):

vertex form: y = a(x-h)^2 + k y = -5(x-(-2))^2 + 10 y = -5(x+2)^2 + 10

OpenStudy (anonymous):

thats it?

jimthompson5910 (jim_thompson5910):

what is the axis of symmetry?

OpenStudy (anonymous):

not sure

jimthompson5910 (jim_thompson5910):

x = h is the axis of symmetry in general

OpenStudy (anonymous):

2

jimthompson5910 (jim_thompson5910):

remember the form is x - h

jimthompson5910 (jim_thompson5910):

go back where I state what the vertex is

OpenStudy (anonymous):

dont get it

jimthompson5910 (jim_thompson5910):

where I said (h,k)

OpenStudy (anonymous):

-2,10

jimthompson5910 (jim_thompson5910):

so h = ???

OpenStudy (anonymous):

-2

jimthompson5910 (jim_thompson5910):

h is the x coordinate of the vertex it also helps form the axis of symmetry

jimthompson5910 (jim_thompson5910):

so the axis of symmetry is x = -2

OpenStudy (anonymous):

http://gyazo.com/42f0e990ff96d3e4edc89ca44ba1844c and help on this please

jimthompson5910 (jim_thompson5910):

are you familiar with the AC method?

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

ok go ahead and read this https://people.richland.edu/james/misc/acmeth.html it provides the basic idea and some examples

OpenStudy (anonymous):

not sure how to start it

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

what are a,b, & c?

OpenStudy (anonymous):

a = -15 b = 2 c = x

jimthompson5910 (jim_thompson5910):

a = 2 b = 1 c = -15

jimthompson5910 (jim_thompson5910):

what is a*c equal to?

OpenStudy (anonymous):

0

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

30

OpenStudy (anonymous):

-30

jimthompson5910 (jim_thompson5910):

closer, but no

jimthompson5910 (jim_thompson5910):

yeah -30

jimthompson5910 (jim_thompson5910):

now you need to find two numbers that a) multiply to -30 AND b) add to 1

OpenStudy (anonymous):

15 x -2 0 + 1

jimthompson5910 (jim_thompson5910):

notice how 15 plus -2 = 13 we want the two numbers to add to 1 as well

OpenStudy (anonymous):

6 x -5

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

very good

jimthompson5910 (jim_thompson5910):

so break up 1x into 6x - 5x

jimthompson5910 (jim_thompson5910):

we now have 2x^2 + 6x - 5x - 15 = 0 factor by grouping

jimthompson5910 (jim_thompson5910):

are you familiar with factor by grouping?

OpenStudy (anonymous):

yes but this one is confusing

jimthompson5910 (jim_thompson5910):

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