Mathematics
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OpenStudy (anonymous):
MEDAL HELP PLEASE http://gyazo.com/746c18162b0dcbc563c5743166573f60
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OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
first you need to find the x coordinate of the vertex
use the formula x = -b/(2a)
jimthompson5910 (jim_thompson5910):
f(x) = -5x^2 - 20x - 10 is in the form y = ax^2 + bx + c
a = -5
b = -20
c = -10
jimthompson5910 (jim_thompson5910):
so you'll plug a = -5 and b = -20 into x = -b/(2a) to get x = ??
OpenStudy (anonymous):
x = -100?
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jimthompson5910 (jim_thompson5910):
no you divide, not multiply
jimthompson5910 (jim_thompson5910):
/ means division
OpenStudy (anonymous):
-2
jimthompson5910 (jim_thompson5910):
now plug that into f(x) to get f(-2) = ???
OpenStudy (anonymous):
100- (-40) - 100?
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OpenStudy (anonymous):
10*
jimthompson5910 (jim_thompson5910):
so because f(-2) = 10, we know the vertex is the point (-2,10)
jimthompson5910 (jim_thompson5910):
vertex: (h,k) = (-2,10) ----> h = -2 and k = 10
jimthompson5910 (jim_thompson5910):
vertex form:
y = a(x-h)^2 + k
y = -5(x-(-2))^2 + 10
y = -5(x+2)^2 + 10
OpenStudy (anonymous):
thats it?
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jimthompson5910 (jim_thompson5910):
what is the axis of symmetry?
OpenStudy (anonymous):
not sure
jimthompson5910 (jim_thompson5910):
x = h is the axis of symmetry in general
OpenStudy (anonymous):
2
jimthompson5910 (jim_thompson5910):
remember the form is x - h
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jimthompson5910 (jim_thompson5910):
go back where I state what the vertex is
OpenStudy (anonymous):
dont get it
jimthompson5910 (jim_thompson5910):
where I said (h,k)
OpenStudy (anonymous):
-2,10
jimthompson5910 (jim_thompson5910):
so h = ???
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OpenStudy (anonymous):
-2
jimthompson5910 (jim_thompson5910):
h is the x coordinate of the vertex
it also helps form the axis of symmetry
jimthompson5910 (jim_thompson5910):
so the axis of symmetry is x = -2
jimthompson5910 (jim_thompson5910):
are you familiar with the AC method?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
not sure how to start it
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what are a,b, & c?
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OpenStudy (anonymous):
a = -15 b = 2 c = x
jimthompson5910 (jim_thompson5910):
a = 2
b = 1
c = -15
jimthompson5910 (jim_thompson5910):
what is a*c equal to?
OpenStudy (anonymous):
0
jimthompson5910 (jim_thompson5910):
no
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OpenStudy (anonymous):
30
OpenStudy (anonymous):
-30
jimthompson5910 (jim_thompson5910):
closer, but no
jimthompson5910 (jim_thompson5910):
yeah -30
jimthompson5910 (jim_thompson5910):
now you need to find two numbers that
a) multiply to -30
AND
b) add to 1
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OpenStudy (anonymous):
15 x -2
0 + 1
jimthompson5910 (jim_thompson5910):
notice how 15 plus -2 = 13
we want the two numbers to add to 1 as well
OpenStudy (anonymous):
6 x -5
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
very good
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jimthompson5910 (jim_thompson5910):
so break up 1x into 6x - 5x
jimthompson5910 (jim_thompson5910):
we now have 2x^2 + 6x - 5x - 15 = 0
factor by grouping
jimthompson5910 (jim_thompson5910):
are you familiar with factor by grouping?
OpenStudy (anonymous):
yes but this one is confusing
jimthompson5910 (jim_thompson5910):
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