Question

Please help!!!
Simplify the rational expression. State any restrictions on the variable

Answer 1

k^2-4k-5
k^2-5k+k-5
k(k-5)+(k-5)=(k-5)(k+1) it is denominator

Answer 2

denominator should not be equal to 0 ...bcoa it will make expression infinity
as anything/0= infinity
\[k \neq 5 ; k \neq-1\]

Answer 3

k^2-k-2
k^2-2k+k-2
=k(k-2)+(k-2)
=(k-2)(k+1) numerator

Answer 4

\[\frac{ (k-2) (k+1)}{ (k-5)(k+1) }=\frac{ k-2 }{ k-5 }\]

Answer 5

as k+1 will be cancelled

Answer 6

\[k \neq 5\] and \[k \neq -1 \] are the restriction

Answer 7

I think it's going to be either D or C just not sure which one

Answer 8

check the restriction ...which one macth with ours??