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What are the steps for the derivative of 2^(3x)?
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chain rule u =3x du = 3 \[\frac{d}{du} 2^u = \ln(2) 2^u\] so answer is: \[3 \ln(2) 2^{3x}\]
I found this, but the answer is different..
they are equal just different forms 2^3 = 8
like this (2^3)^x=2^(3x), just multiplying the exponents?
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yes like that
ok, thank you
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