HELP!! - The radius of a spherical balloon is increasing at a rate of 2cm per minute. how fast is the volume changing when the radius is 14 centimeters.
Note: The volume of a sphere is given by V= (4/3)(pi)(r)^3
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OpenStudy (anonymous):
volume is a function of radius, and radius is a function of time
OpenStudy (anonymous):
ok, whats my next step
OpenStudy (anonymous):
differentiate everything with respect to time
OpenStudy (anonymous):
not sure what i differentiate
OpenStudy (anonymous):
both sides of the equation
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OpenStudy (anonymous):
the right side differentiated with respect to t is (4)(pi)(r)^2(dr/dt)
OpenStudy (anonymous):
can you figure out the left side?
OpenStudy (anonymous):
V?
wouldnt it just be dx/dt?
OpenStudy (anonymous):
dV/dt yeah
OpenStudy (anonymous):
so dV/dt = (4)(pi)(r)^2(dr/dt)
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OpenStudy (anonymous):
you are given r
OpenStudy (anonymous):
r for radius so 10
OpenStudy (anonymous):
uhh the problem says 14cm according to what i'm reading at the top
OpenStudy (anonymous):
yeah my bad 14
OpenStudy (anonymous):
you are also given dr/dt = 2
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OpenStudy (anonymous):
so you can plug those into the equation we just differentiated