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Mathematics 10 Online
OpenStudy (anonymous):

HELP!! - The radius of a spherical balloon is increasing at a rate of 2cm per minute. how fast is the volume changing when the radius is 14 centimeters. Note: The volume of a sphere is given by V= (4/3)(pi)(r)^3

OpenStudy (anonymous):

volume is a function of radius, and radius is a function of time

OpenStudy (anonymous):

ok, whats my next step

OpenStudy (anonymous):

differentiate everything with respect to time

OpenStudy (anonymous):

not sure what i differentiate

OpenStudy (anonymous):

both sides of the equation

OpenStudy (anonymous):

the right side differentiated with respect to t is (4)(pi)(r)^2(dr/dt)

OpenStudy (anonymous):

can you figure out the left side?

OpenStudy (anonymous):

V? wouldnt it just be dx/dt?

OpenStudy (anonymous):

dV/dt yeah

OpenStudy (anonymous):

so dV/dt = (4)(pi)(r)^2(dr/dt)

OpenStudy (anonymous):

you are given r

OpenStudy (anonymous):

r for radius so 10

OpenStudy (anonymous):

uhh the problem says 14cm according to what i'm reading at the top

OpenStudy (anonymous):

yeah my bad 14

OpenStudy (anonymous):

you are also given dr/dt = 2

OpenStudy (anonymous):

so you can plug those into the equation we just differentiated

OpenStudy (anonymous):

and solve for dV/dt

OpenStudy (anonymous):

1568pi

OpenStudy (anonymous):

and its correct.. thank you

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